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A,B,C together can do a piece of work in 10 days.All the three started workingat it together and after 4 days,A left.Then,B and C together completed the work in 10 more days.In how many days can complete a work alone ?

Correct Answer: 25

Explanation:

(A+B+C) do 1 work in 10 days.


So (A+B+C)'s 1 day work=1/10 and as they work together for 4 days so workdone by them in 4 days=4/10=2/5



Remaining work=1-2/5=3/5


 


(B+C) take 10 more days to complete 3/5 work. So( B+C)'s 1 day work=3/50



Now A'S 1 day work=(A+B+C)'s 1 day work - (B+C)'s 1 day work=1/10-3/50=1/25


A does 1/25 work in in 1 day


Therefore 1 work in 25 days.


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