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3 men, 4 women and 6 children can complete a work in 7 days. A woman does double the work a man does and a child does half the work a man does. How many women alone can complete this work in 7 days ?

Correct Answer: 7

Explanation:

Let 1 woman's 1 day work = x.


Then, 1 man's 1 day work = x/2 and 1 child's 1 day work  x/4.


So, (3x/2 + 4x + + 6x/4) = 1/7


28x/4 = 1/7 => x = 1/49


1 woman alone can complete the work in 49 days.


So, to complete the work in 7 days, number of women required = 49/7 = 7.


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