Home » Aptitude » Time and Work

If 6 men and 8 boys can do a piece of work in 10 days while 26 men and 48 boys can do the same in 2 days what is time taken by 15 men and 20 boys?

Correct Answer: 4 days

Explanation:

Given that 


6 men and 8 boys can do a piece of work in 10 days 


26 men and 48 boys can do the same in 2 days


 


As the work done is equal,


10(6M + 8B) = 2(26M + 48B)


60M + 80B = 52M + 96B


=> M = 2B


=> B = M/2 ……(1)


 


Now Put (1) in 15M + 20B


=> 15M + 10M = 25M


Now, 6M + 8B in 10 days


=> (6M + 4M) 10 = 100M


Then D(25M) = 100M


=> D = 4 days.


← Previous Question Next Question→

More Questions from Time and Work

Discussion & Comments

No comments yet. Be the first to comment!
Join Discussion