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16 women can do a piece of work in 10 days while 15 men can do the same work in 12 days. All men and all women work alternately starting with all men, then find the time taken by them to complete the whole work?

Correct Answer: 10 5/2 days

Explanation:

Let efficiency of every man and every woman be 'm' unit/day and 'w' unit/day respectively


15×12×m = 10×16×w


⇒ m/w = 8/9


Total work = 15 × 12 × 9 = 1620 units


In 2 days, total work done = 15 x 9 + 16 x 8 = 263 units


So, in 10 days work done will be = 263 × 5 = 1315 units


Remaining work will be done in = (1620-1315)/(15×8) = 5/2 days


Total days = 10 5/2 days.


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