Question 1

If Hema walks at 12 km/hr instead of 8 km/hr, she would have walked 20 km more. The actual distance travelled by Hema is ?

Accepted Answer

Let the actual distance travelled be x km. Then x/8=(x+20)/12 => 12x = 8x + 160 => 4x = 160 => x = 40 km.

Question 2

A train of length 250 m crosses a bridge of length 150m in 20 seconds. What is the speed of the train?

Accepted Answer

Length of the train= 250m Length of the bridge= 150m Time taken= 20s Speed = Distance/ Time = 400/20= 20 m/s =72 km/h

Question 3

Two trains running in opposite directions cross a pole placed on the platform in 47 seconds and 31 seconds respectively. If they cross each other in 33 seconds, what is the ratio of their speeds?

Accepted Answer

Let the speed of the trains be x and y respectively length of train1 = 47x length of train2 = 31y Relative speed= x + y Time taken to cross each other = 33 s => 47 x + 31 y x + y = 33 => (47x + 31 y) = 33(x + y) => 14x = 2y => x/y = 2/14 = 1/7 = 1:7

Question 4

A jeep travels a certain distance taking 6 hrs in forward journey, during the return journey increased speed 12km/hr takes the times 4 hrs. What is the distance travelled by the jeep is ?

Accepted Answer

Given a jeep travels a certain distance taking 6 hrs in forward journey During the return journey, it takes 4 hrs with an increased speed 12 km/hr Let 'x' be the distance. Now, speed is given by distance/time. Here the difference between both speeds = 12 x 4 - x 6 = 12 3 x - 2 x 12 = 12 => x = 144 km Therefore, the distance travelled by the jeep in forward or return journey is x = 144 km.

Question 5

'K' cycled from A to B at 10 kmph and returned at the rate of 9 kmph. 'L' cycled both ways at 12 kmph. In the whole journey 'L' took 10 minutes less than 'K'. Find the distance between A and B ?

Accepted Answer

Let 'd' be the distance between A and B K -time = d/10 + d/9 = 19d/90 hours L -time = 2d/12 = d/6 hours We know that, 10 min = 1/6 hours Thus, time difference between K and L is given as 10 minutes. => 19d/90 - d/6 = 1/6 => (19d-15d)/90 = 1/6 => 4d/90 = 1/6 Thus, d= 15/4 km = 3.75 km. hence the distance between A and B is 3.75 km.

Question 6

Laxmi and Prasanna set on a journey. Laxmi moves northwards at a speed of 20kmph and Prasanna moves southward at a speed of 30 kmph. How far will be Prasanna from Laxmi after 60 minutes ?

Accepted Answer

We know 60 min = 1 hr Total northward Laxmi's distance = 20kmph x 1hr = 20 km Total southward Prasanna's distance = 30kmph x 1hr = 30 km Total distance between Prasanna and Laxmi is = 20 + 30 = 50 km.

Question 7

A train-A passes a stationary train B and a pole in 24 sec and 9 sec respectively. If the speed of train A is 48 kmph, what is the length of train B?

Accepted Answer

Length of train A = 48 x 9 x 5/18 = 120 mts Length of train B = 48 x 24 x 5/18 - 120 => 320 - 120 = 200 mts.

Question 8

Two cyclists P and Q cycle at 20 km/hr and 25 km/hr towards each other. What was the distance (in kms) between them when they started if they met after 56 minutes?

Accepted Answer

42

Question 9

A train travels 325 km in 3.5 hours and 470 km in 4 hours. Find the average speed of train ?

Accepted Answer

As we know that Speed = Distance / Time for average speed = Total Distance / Total Time Taken Thus, Total Distance = 325 + 470 = 795 km Thus, Total Speed = 7.5 hrs Average Speed = 795/7.5 => 106 kmph.

Question 10

You drive to the store at 20 kmph and return by the same route at 30 kmph. Discounting the time spent at the store, what was your average speed ?

Accepted Answer

Average speed=total distance/total time Let distance to store be K then, total time =(K/20)+(K/30)=K/12 and, total time =(2K) so average speed= 2K / (K/12) = 24kmph.

Question 11

Ali and Faizer are 27m apart. They both start walking and meet 9 hrs later, if they travel in the same direction and meet after 3 hrs if they walk in opposite dirction, Ali’s speed must most likely be ?

Accepted Answer

let, speed of Ali=X mph and Faizer=Y mph Now, relative speed when Ali is walking int the same direction with Faizer= (X-Y)mph hence, according to question, 27/(X-Y)=9 ; solving X-Y=3; --- (1) Now relative speed when walking in the opposite direction= (X+Y) mph hence, according to question, 27/(X+y)=3; solving X+Y=9; --- (2) solving 1 and 2 we get X=6 and Y=3, where X is the speed of Ali.

Question 12

Excluding stoppages, the average speed of a bus is 60 km/hr and including stoppages, the average speed of the bus is 40 km/hr. For how many minutes does the bus stop per hour ?

Accepted Answer

In 1hr, the bus covers 60 km without stoppages and 40 km with stoppages. Stoppage time = time take to travel (60 - 40) km i.e 20 km at 60 km/hr. stoppage time = 20/60 hrs = 20 min.

Question 13

How many seconds will a 800 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?

Accepted Answer

Here distance d = 800 mts speed s = 63 - 3 = 60 kmph = 60 x 5/18 m/s time t = 800 x 18 60 x 5 = 48 sec.

Question 14

A person travels from K to L a speed of 50 km/hr and returns by increasing his speed by 50%. What is his average speed for both the trips ?

Accepted Answer

Speed on return trip = 150% of 50 = 75 km/hr. Average speed = (2 x 50 x 75)/(50 + 75) = 60 km/hr.

Question 15

Joel travels the first 3 hours of his journey at 60 mph speed and the remaining 5 hours at 24 mph speed. What is the average speed of Joel's travel in kmph ?

Accepted Answer

Average speed = Total distance / Total time. Total distance traveled by Joel = Distance covered in the first 3 hours + Distance covered in the next 5 hours. Distance covered in the first 3 hours = 3 x 60 = 180 miles Distance covered in the next 5 hours = 5 x 24 = 120 miles Therefore, total distance traveled = 180 + 120 = 300 miles. Total time taken = 3 + 5 = 8 hours. Average speed = 300/8 = 37.5 mph. we know that 1 mile = 1.6 kms => 37.5 miles = 37.5 x 1.6 = 60 kms Average speed in Kmph = 60 kmph.

Question 16

Two trains are running with speeds 30 kmph and 58 kmph respectively in the same direction. A man in the slower train passes the faster train in 18 seconds. Find the length of the faster train?

Accepted Answer

Speeds of two trains = 30 kmph and 58 kmph => Relative speed = 58 - 30 = 28 kmph = 28 x 5/18 m/s = 70/9 m/s Given a man takes time to cross length of faster train = 18 sec Now, required Length of faster train = speed x time = 70/9 x 18 = 140 mts.

Question 17

Sabrina travelled 8 km/hr on foot and 13 km/hr on cycle. She travelled a distance of 84 km in 8 hours. Forhow many hours did she cycle?

Accepted Answer

4

Question 18

Two cars start from a house at an interval of 10 min and travel at a speed of 20 kmph. With how much speed should a woman coming from the opposite direction towards the house travel, to meet the cars at an interval of 8 min?

Accepted Answer

5

Question 19

Two cars travel from city A to city B at a speed of 36 and 54 km/hr respectively. If one car takes 3.5 hours lesser time than the other car for the journey, then the distance between City A and City B is

Accepted Answer

378 km

Question 20

Ruchir walks at 20 km/hr and Rukma cycles at 25 km/hr towards each other. What was the distance between them when they started if they meet after 48 minutes?

Accepted Answer

36 km

Time and Distance Questions