Truth among set relations for BOWL / ELBOW / BELLOW: Let A = letters of 'BOWL', B = letters of 'ELBOW', C = letters of 'BELLOW'. Which statement is false?

Introduction / Context:We compare sets made from letters of words (duplicates ignored). The task is to identify the false statement among four relations.

Given Data / Assumptions:

• A = {B, O, W, L}
• B = {E, L, B, O, W}
• C = {B, E, L, O, W}

Concept / Approach:Compute each relation by direct comparison of membership.

Step-by-Step Solution:A ⊂ B: true (A's four letters are all in B)B = C: true (same five letters)B ⊃ C: true if interpreted as superset allowing equality'B is a proper subset of C': false because B and C are equal

Verification / Alternative check:Enumerations confirm equality of B and C, invalidating the 'proper subset' claim.

Why Other Options Are Wrong:They are true under standard set interpretations (A ⊂ B, B ⊃ C, B = C).

Common Pitfalls:Confusing superset '⊃' with proper superset; here, equality makes 'proper subset' false.

Final Answer:B is a proper subset of C.