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Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

Difficulty: Medium

Correct Answer: 48 seconds

Explanation:

We are given:

  • Speed of Train 1 = 60 km/h
  • Speed of Train 2 = 90 km/h
  • Length of Train 1 = 1.10 km = 1100 m
  • Length of Train 2 = 0.90 km = 900 m

Step 1: Calculate total distance to be covered

Both trains are moving in opposite directions, so they will cross each other completely.
Total distance = Length of Train 1 + Length of Train 2
= 1100 + 900 = 2000 meters

Step 2: Convert relative speed to m/s

Relative Speed = 60 + 90 = 150 km/h
Convert to m/s: 150 × (1000 / 3600) = 41.67 m/s

Step 3: Calculate time using the formula

Time = Distance / Speed
= 2000 / 41.67 ≈ 48 seconds

Final Answer:

The time taken by the slower train to cross the faster train is approximately 48 seconds
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