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Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

Correct Answer: 60 km/hr

Explanation:

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.


Relative speed = (x + 2x) m/sec = 3x m/sec.



(100 + 100) = 3x
8


⟹ 24x = 200



x = 25 .
3



So, speed of the faster train = 50 m/sec
3



   = 50 x 18 ❩km/hr
3 5


   = 60 km/hr.


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