Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?

We are given:

• Distance between stations A and B = 110 km
• Train A starts at 7 a.m. at 20 km/h
• Train B starts at 8 a.m. at 25 km/h

Step 1: Distance covered by Train A before Train B starts
From 7 a.m. to 8 a.m., Train A travels = 20 × 1 = 20 kmRemaining distance = 110 – 20 = 90 km

Step 2: Relative speed after 8 a.m.
Relative speed = 20 + 25 = 45 km/h

Step 3: Time taken to meet
Time = 90 / 45 = 2 hours

Final Answer:
They meet at 8 a.m. + 2 hours = 10 a.m.