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A train moves past a telegraph post and a bridge 264 m long in 8 seconds and 20 seconds respectively. What is the speed of the train?

Correct Answer: 79.2 km/hr

Explanation:

Let the length of the train be x metres and its speed by y m/sec.


Then, x = 8     ⟹     x = 8y
y



Now, x + 264 = y
20


⟹ 8y + 264 = 20y


y = 22.



∴ Speed = 22 m/sec = 22 x 18 km/hr = 79.2 km/hr.
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