Correct Answer: 13 102
Explanation:
Then, n(S) = 52C2 = | (52 x 51) | = 1326. |
(2 x 1) |
Let E = event of getting 1 spade and 1 heart.
∴ n(E) | = number of ways of choosing 1 spade out of 13 and 1 heart out of 13 |
= (13C1 x 13C1) | |
= (13 x 13) | |
= 169. |
∴ P(E) = | n(E) | = | 169 | = | 13 | . |
n(S) | 1326 | 102 |
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