Curioustab

Home » Aptitude » Probability

In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?

1 3
3 4
7 19
8 21
9 21

Correct Answer: 1 3

Explanation:

Total number of balls = (8 + 7 + 6) = 21.

Let E	= event that the ball drawn is neither red nor green
	= event that the ball drawn is blue.

∴ n(E) = 7.

∴ P(E) =	n(E)	=	7	=	1	.
	n(S)		21		3

← Previous Question Next Question→

More Questions from Probability

Three unbiased coins are tossed. What is the probability of getting at most two heads?
A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
What is the probability that a number selected from the numbers 1, 2, 3, 4, 5....16 is a prime number?
An urn contains 9 red, 7 white and 4 black balls. A ball is drawn at random. What is the probability that the ball drawn is not red?
In a lottery there are 20 prizes and 15 blanks. What is the probability of getting prize?
The odds in favour of an event are 3 : 5. The probability of occurrence of the event is?
The probability of getting heads in both trials when a balanced coin is tossed twice will be?
A number is chosen at random among the first 120 natural numbers. The probability of the number chosen being a multiple of 5 or 15 is?
A bag contains 7 white and 9 red balls. The probability of drawing a white ball is?

Discussion & Comments

No comments yet. Be the first to comment!

Join Discussion