A box has 8 red, 7 blue, and 6 green balls. One ball is drawn at random. What is the probability that it is neither red nor green?

Given data

• Red = 8, Blue = 7, Green = 6; Total = 21.

Concept/Approach
Neither red nor green means blue.

Step-by-Step calculation
P(blue) = 7 ÷ 21 = 1 ÷ 3

Verification/Alternative
Complement: 1 − P(red or green) = 1 − (8+6)÷21 = 1 − 14÷21 = 7÷21.

Final Answer
1/3