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Three unbiased coins are tossed. What is the probability of getting at most two heads?

3/4
1/4
3/8
7/8

Correct Answer: 7/8

Explanation:

Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}

Let E = event of getting at most two heads.

Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.

∴ P(E) =	n(E)	=	7	.
	n(S)		8

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