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If three unbiased coins are tossed simultaneously, then the probability of exactly two heads, is

1/8
2/8
3/8
4/8

Correct Answer: 3/8

Explanation:

n(S) = 2³ = 8
Let E = Event of getting exactly two heads
= {(H, H, T), (H, T ,H), (T, H, H)}
⇒ n(E) = 3
∴ required probability = 3/8

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