An urn contains 3 red and 4 green marbles. If three marbles are picked at random, what is the probability that two are green and one is red?

3/7
18/35
5/14
4/21

Correct Answer: 18/35

Explanation:

Number of ways to select 3 marbles out of 7 marbles = n(s) = ⁷C₃ = 35
Probability that 2 are green and 1 is red = n(E) = ⁴C₂ x ³C₁ = 18
∴ Required probability = 18/35

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