If two caps are picked at random, what is the probability that both are blue?

1/6
1/10
1/12
None of these

Correct Answer: None of these

Explanation:

Total number of caps = 2 + 4 + 5 + 1 = 12
Total number of outcomes = n(S) = ¹²C₂ = 66
Favorable number of outcomes = n(E) = ²C₂ = 1
∴ Required probability = 1/66

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