Tap A fills a tank in 25 minutes, Tap B fills it in 40 minutes, and Tap C empties it in 30 minutes. If all three taps are opened together on an empty tank, will the tank be filled or emptied, and in how many minutes?

Aptitude Pipes and Cistern Difficulty: Medium
Choose an option
Answer

Correct Answer: None of these

Explanation

Introduction / Context:Sum the two inlet rates and subtract the outlet rate. If the net is positive, the tank fills; if negative, it empties. The magnitude of the net rate yields the time for a full tank (if filling) from empty.

Given Data / Assumptions:

  • A = 1/25 tank/min.
  • B = 1/40 tank/min.
  • C = −1/30 tank/min.

Concept / Approach:Net rate r = 1/25 + 1/40 − 1/30. If r > 0, time to fill = 1/r minutes.

Step-by-Step Solution:

LCM 600 ⇒ r = (24 + 15 − 20)/600 = 19/600 tank/min.Since r > 0, the tank fills. Time = 1 / (19/600) = 600/19 ≈ 31.58 minutes.

Verification / Alternative check:31.58 min * 19/600 ≈ 1 tank, confirming.

Why Other Options Are Wrong:Given numeric options do not match 600/19 minutes; therefore “None of these.”

Common Pitfalls:Arithmetic with mixed denominators or assuming integer results. The exact fraction 600/19 is correct.

Final Answer:None of these (net fill time = 600/19 minutes ≈ 31.58 min)

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