H.C.F. of $4 \times 27 \times 3125$, $8 \times 9 \times 25 \times 7$ & $16 \times 81 \times 5 \times 11 \times 49$ is
Aptitude
HCF and LCM
Difficulty: Medium
Choose an option
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A$180$
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B$360$
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C$540$
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D$1260$
Answer
Correct Answer: $180$
Explanation
### Concept & Strategy
Before applying the HCF rule for exponential expressions, all numbers must be converted into their **prime** factorized forms. The given numbers contain composite bases (like $4, 27, 25, 16, 81$, etc.) which must be broken down first.
Once converted to prime bases, the HCF is the product of the lowest powers of the common prime factors.
### Step-by-Step Solution
* **Given:**
Expression 1: $4 \times 27 \times 3125$
Expression 2: $8 \times 9 \times 25 \times 7$
Expression 3: $16 \times 81 \times 5 \times 11 \times 49$
* **Calculation / Deduction:**
1. **Convert Expression 1 to Primes:**
$4 = 2^2$
$27 = 3^3$
$3125 = 5^5$
So, Exp 1 = $2^2 \times 3^3 \times 5^5$
2. **Convert Expression 2 to Primes:**
$8 = 2^3$, $9 = 3^2$, $25 = 5^2$, $7 = 7^1$
So, Exp 2 = $2^3 \times 3^2 \times 5^2 \times 7^1$
3. **Convert Expression 3 to Primes:**
$16 = 2^4$, $81 = 3^4$, $5 = 5^1$, $11 = 11^1$, $49 = 7^2$
So, Exp 3 = $2^4 \times 3^4 \times 5^1 \times 11^1 \times 7^2$
4. **Find Common Primes:** The bases present in *all three* expressions are $2, 3$, and $5$. (Ignore $7$ and $11$ as they are not in Exp 1).
5. **Extract Lowest Powers:**
Lowest power of $2$ is $2^2$ (from Exp 1)
Lowest power of $3$ is $3^2$ (from Exp 2)
Lowest power of $5$ is $5^1$ (from Exp 3)
6. **Calculate HCF:**
$$HCF = 2^2 \times 3^2 \times 5^1$$
$$HCF = 4 \times 9 \times 5 = 180$$
### Exam Strategy & Shortcut
**Targeting the Smallest Component:**
Look for the smallest factor among the composite groupings.
For base 5: The third expression has a standalone "$5$". This means the highest power of 5 in the HCF can only be $5^1 = 5$.
For base 2: The first expression has "$4$". The highest power of 2 in the HCF can only be $4$.
For base 3: The second expression has "$9$". The highest power of 3 in the HCF can only be $9$.
Multiply these limiting factors directly: $4 \times 9 \times 5 = 180$. You don't need to calculate $3125$ or $81$ at all.
### Common Pitfall
Applying the HCF rule directly to the composite numbers without prime-factorizing them first. If you just look for "common numbers" in the raw expressions, you will completely miss the hidden prime factors shared across the composite bases.
### Final Answer
**Therefore, the correct answer is $180$.**