The H.C.F. of $\frac{9}{10}, \frac{12}{25}, \frac{18}{35}$ and $\frac{21}{40}$ is
Aptitude
HCF and LCM
Difficulty: Medium
Choose an option
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A$\frac{3}{5}$
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B$\frac{252}{5}$
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C$\frac{3}{1400}$
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D$\frac{63}{700}$
Answer
Correct Answer: $\frac{3}{1400}$
Explanation
### Concept & Formula
When calculating the Highest Common Factor (HCF) of several fractions, we apply the foundational fraction rule:
$$\text{H.C.F.} = \frac{\text{H.C.F. of Numerators}}{\text{L.C.M. of Denominators}}$$
### Step-by-Step Solution
* **Given Fractions:** $\frac{9}{10}$, $\frac{12}{25}$, $\frac{18}{35}$, and $\frac{21}{40}$.
* **Step 1: Calculate the HCF of the numerators ($9, 12, 18, 21$).**
All of these numbers are clearly multiples of $3$.
$9 = 3 \times 3$
$12 = 3 \times 4$
$18 = 3 \times 6$
$21 = 3 \times 7$
The highest number that divides all of them is $3$. So, the numerator of our answer is $3$.
* **Step 2: Calculate the LCM of the denominators ($10, 25, 35, 40$).**
Prime factorize each:
$10 = 2 \times 5$
$25 = 5^2$
$35 = 5 \times 7$
$40 = 2^3 \times 5$
Take the highest power of each prime factor ($2, 5, 7$):
$$LCM = 2^3 \times 5^2 \times 7$$
$$LCM = 8 \times 25 \times 7$$
$$LCM = 200 \times 7 = 1400$$
* **Step 3: Assemble the fraction.**
$$\text{Result} = \frac{3}{1400}$$
### Exam Strategy & Shortcut
Calculate the HCF of the numerators first, which is $3$. Instantly eliminate option (b) and (d). You are left with $\frac{3}{5}$ and $\frac{3}{1400}$. Now look at the denominators. For the denominator of the answer to be $5$, the LCM of $10, 25, 35, 40$ would have to be $5$, which is logically impossible (the LCM must be greater than or equal to the largest number, $40$). Thus, without doing the heavy math, option (c) is the only mathematically viable choice.
### Common Pitfall
Calculating the full LCM for the denominators using the ladder method wastes a lot of time. In multiple-choice exams, determining just the numerator and doing a quick logical check on the remaining denominator options is the key to finishing on time.
### Final Answer
**Therefore, the correct answer is $\frac{3}{1400}$.**