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If the perimeters of a square and a rectangle are the same, then the area a & b enclosed by them would satisfy the condition:

Correct Answer: a>b

Explanation:

Take a square of side 4cm and a rectangle having l=6cm and b=2cm


then perimeter of square = perimeter of rectangle


area of square = 16 sq.cm


area of rectangle = 12 sq.cm


Hence a >b


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