Step size of a 6-bit ADC over a 0–7 V input range An analog signal varies from 0 V to 7 V and is digitized by a 6-bit ADC. What analog value does each 1-LSB step represent on the digital output?

Difficulty: Easy

Correct Answer: 0.109 V

Explanation:


Introduction / Context:
Knowing the LSB size of an ADC allows quick estimation of quantization error and measurement resolution across a given input range.



Given Data / Assumptions:

  • Input span: 0 to 7 V.
  • Resolution: 6 bits → 64 codes.
  • Ideal mid-tread behavior assumed for step size calculation.


Concept / Approach:
The LSB step size for an ideal ADC is Step = Full-Scale Range / 2^N. Here, N = 6, so 2^N = 64.



Step-by-Step Solution:

Compute step: 7 V / 64 = 0.109375 V.Round to three decimals: ≈ 0.109 V.Therefore, each increment in the digital code corresponds to about 0.109 V of the input.


Verification / Alternative check:
2^6 = 64; 0.1 V × 64 = 6.4 V, so the precise 0.109375 V step is consistent with a 7 V span.



Why Other Options Are Wrong:

  • 0.111 V: Close but not exact; it overestimates the step.
  • 1.17 V / 0.857 V: These are far too large; they would imply minimal resolution (3–8 steps total).


Common Pitfalls:

  • Dividing by 2^N − 1 for step size; while code count is 0..63, the step size calculation uses 2^N in ideal mid-tread models.


Final Answer:
0.109 V

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