Three friends had dinner at a restaurant. When the bill was received, Amita paid $\frac{2}{3}$ as much as Veena paid and Veena paid $\frac{1}{2}$ as much as Tanya paid. What fraction of the bill did Veena pay?
Aptitude
Simplification
Difficulty: Medium
Choose an option
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A\frac{1}{3}
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B\frac{3}{11}
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C\frac{12}{31}
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D\frac{5}{8}
Answer
Correct Answer: \frac{3}{11}
Explanation
### Concept & Strategy
Express each person's relative contribution as a single ratio chain, similar to multi-variable component sharing.
Let $A$ = Amita, $V$ = Veena, $T$ = Tanya.
$$A = \frac{2}{3}V \implies \frac{A}{V} = \frac{2}{3}$$
$$V = \frac{1}{2}T \implies \frac{V}{T} = \frac{1}{2}$$
### Step-by-Step Solution
* **Unify the component ratios:**
We need $V$ to be identical in both ratios. The common value for 3 and 1 is 3.
Multiply the second ratio ($V:T = 1:2$) by 3:
$$V : T = 3 : 6$$
Now join them:
$$A : V : T = 2 : 3 : 6$$
* **Calculate the total bill parts:**
$$\text{Total Parts} = 2 + 3 + 6 = 11 \text{ parts}$$
* **Determine Veena's fraction of the total:**
$$\text{Veena's Fraction} = \frac{\text{Veena's Parts}}{\text{Total Parts}} = \frac{3}{11}$$
### Exam Strategy & Shortcut
Assume a smart concrete value for the final independent variable, Tanya. Let Tanya pay ₹ 6 (the LCM of the denominators 3 and 2).
* Tanya = ₹ 6
* Veena = $\frac{1}{2} \times 6 =$ ₹ 3
* Amita = $\frac{2}{3} \times 3 =$ ₹ 2
* Total bill = $6 + 3 + 2 =$ ₹ 11
* Veena's portion = $\frac{3}{11}$
This entirely avoids algebraic variables.
### Common Pitfall
Summing the initial denominators directly without adjusting them to form a cohesive, unified ratio expression.
### Final Answer
**Therefore, the correct answer is \frac{3}{11}.**