If A, G, and H denote the arithmetic mean, geometric mean, and harmonic mean (for two positive numbers), which identity holds among them?

Difficulty: Easy

Correct Answer: A x H = G2

Explanation:


Introduction / Context:
For two positive numbers, the classical relationships among arithmetic mean (A), geometric mean (G), and harmonic mean (H) include a useful identity that links them exactly, not just via inequalities.


Given Data / Assumptions:

  • Two positive numbers x and y.
  • Definitions: A = (x + y)/2, G = sqrt(xy), H = 2xy/(x + y).


Concept / Approach:

  • Compute A*H using the definitions, and compare to G^2.


Step-by-Step Solution:

A * H = [(x + y)/2] * [2xy/(x + y)] = xyG^2 = (sqrt(xy))^2 = xyTherefore, A * H = G^2


Verification / Alternative check:
Pick x = 4, y = 9: A = 6.5, G = 6, H = 2*36/13 ≈ 5.538; A*H ≈ 36 = G^2; identity holds.


Why Other Options Are Wrong:

  • A × H = G and the ratio forms do not simplify to xy consistently.
  • None of these: Not applicable; A × H = G^2 is exact for two numbers.


Common Pitfalls:

  • Confusing the AM–GM–HM inequalities with this identity.
  • Applying the identity to more than two numbers, where it does not generally hold.


Final Answer:
A × H = G^2

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