Vehicle behaviour on horizontal curves If the centrifugal force on a vehicle negotiating a horizontal curve exceeds the available lateral friction, the vehicle will most likely:

Introduction / Context:On horizontal curves, lateral equilibrium is provided by a combination of superelevation and lateral friction between tire and pavement. When the required centripetal force exceeds what friction (and superelevation) can supply, loss of lateral control occurs.

Given Data / Assumptions:

• Vehicle negotiates a curve of given radius at a given speed.
• Lateral friction factor f represents peak available friction.
• Superelevation may be present but is insufficient to balance demand.

Concept / Approach:The demand is v^2 / r. The supply is g*(e + f) in normalized form, where e is superelevation (as a ratio) and f is friction factor. If v^2/(g r) > e + f, the pavement–tire interface cannot transmit the needed lateral force, leading to side slip or skid.

Step-by-Step Solution:

Verification / Alternative check:Design formula e + f = V^2/(225R) (with V in km/h, R in m) expresses the same balance; demand exceeding supply signals skidding risk.

Why Other Options Are Wrong:“Slip” is a vague term; “not be affected/none” contradicts physics when demand exceeds resistance.

Common Pitfalls:Ignoring wet pavement which lowers f; assuming e alone can compensate indefinitely; using improper units.

Final Answer:skid