Syllogism – Resolve the apparent contradiction Premises: 1) All students in my class are bright. 2) Manish is not bright. What follows?

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Solve this multiple-choice question and choose the correct option.

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Introduction / Context:This is a categorical syllogism that examines class membership based on a property (“bright”). If membership in a set guarantees a property, and an individual lacks that property, then the individual cannot belong to the set. We apply this directly to the class and Manish. Given Data / Assumptions: P1: All students in my class are bright. P2: Manish is not bright. We use standard logic with no hidden premises. Concept / Approach:“All A are B” and “x is not B” implies “x is not A.” Here, A = “students in my class,” B = “bright,” and x = Manish. This is a contrapositive reasoning pattern. Step-by-Step Solution: Translate: Class students -> bright.Given: Manish is not bright.Therefore: Manish cannot be a student in the class. Verification / Alternative check: Assume Manish is a student in the class: then he must be bright (contradiction). Thus, he is not a student in the class. Why Other Options Are Wrong: A: Does not follow; P1 says all class students are bright.B: Irrelevant; effort is not a logical consequence here.C: Overgeneralizes to “all non-bright are non-students,” which is not stated globally.E: Invalid because D follows. Common Pitfalls: Assuming properties about all students everywhere rather than restricting to “my class.” Final Answer:Manish is not a student of my class.

Syllogism – Resolve the apparent contradiction Premises: 1) All students in my class are bright. 2) Manish is not bright. What follows?

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