Syllogism — Goats, tigers, and lions (subset chains): Statements: (a) All goats are tigers. (b) All tigers are lions. Conclusions: I. All tigers are goats. II. All lions are tigers. III. No goat is a lion. IV. No lion is a goat.

Introduction / Context:Two universal inclusions are given. We must avoid both reversing inclusions and drawing unwarranted negatives.

Given Data / Assumptions:

• Goat ⊆ Tiger.
• Tiger ⊆ Lion.

Concept / Approach:From the chain, Goat ⊆ Lion. However, none of the listed conclusions matches this lawful result: (I) reverses inclusion; (II) wrongly claims Lion ⊇ Tiger in the reverse direction; (III) and (IV) assert disjointness that is contradicted or not implied.

Step-by-Step Analysis:1) I “All tigers are goats” is false (wrong direction).2) II “All lions are tigers” is false (reverse inclusion).3) III “No goat is a lion” contradicts Goat ⊆ Lion.4) IV “No lion is a goat” is not implied; goats may be a proper subset of lions.

Verification / Alternative check:Model: Goats (10) ⊆ Tigers (100) ⊆ Lions (1000). None of I–IV is forced true.

Final Answer:None of the conclusions follow.