Syllogism — Carts, cars, and trains (transitivity): Statements: • All carts are cars. • All cars are trains. Conclusions to test: I. All carts are trains. II. All trains are carts.

Introduction / Context:
This item checks transitivity of set inclusion and the common mistake of reversing subset relations.

Given Data / Assumptions:

• All carts are cars (Cart ⊆ Car).
• All cars are trains (Car ⊆ Train).

Concept / Approach:
Subset relations compose: if A ⊆ B and B ⊆ C, then A ⊆ C. But the converse (C ⊆ A) does not follow.

Step-by-Step Solution:
1) Chain the inclusions: Cart ⊆ Car and Car ⊆ Train implies Cart ⊆ Train.2) Conclusion I is therefore correct.3) Conclusion II “All trains are carts” would require Train ⊆ Cart, which is not warranted.

Verification / Alternative check:
Create a model: Carts (20) ⊆ Cars (100) ⊆ Trains (1000). Inclusion works one way only.

Why Other Options Are Wrong:
“Only II,” “Both,” and “Neither” contradict the valid transitive inclusion.

Common Pitfalls:
Converse error: assuming if A ⊆ B then B ⊆ A.

Final Answer:
Only conclusion I follows.