Ages — product and linear relation: The product of Harish’s and Seema’s present ages is 240. Also, twice Seema’s age exceeds Harish’s age by 4 years. Find Seema’s present age in years.

Difficulty: Medium

Correct Answer: 12 years

Explanation:


Introduction / Context:
Here we mix a multiplicative constraint (product of ages) with a linear relationship. Setting variables and solving a quadratic yields the answer efficiently.


Given Data / Assumptions:

  • H * S = 240, where H = Harish, S = Seema.
  • 2S is greater than H by 4 ⇒ 2S = H + 4.


Concept / Approach:
Express H in terms of S from the linear relation, substitute into the product, solve for S, and select the positive, realistic root.


Step-by-Step Solution:

H = 2S − 4.S * (2S − 4) = 240 ⇒ 2S^2 − 4S − 240 = 0.Divide by 2: S^2 − 2S − 120 = 0.Factor: (S − 12)(S + 10) = 0 ⇒ S = 12 (reject −10).Therefore Seema’s age = 12 years.


Verification / Alternative check:

H = 2*12 − 4 = 20; product 20*12 = 240 ✓ and 2S = 24 = H + 4 = 24 ✓


Why Other Options Are Wrong:

  • 20, 10, 14 years do not satisfy both the product and the linear relation simultaneously.


Common Pitfalls:

  • Using H = 2S + 4 instead of H + 4 = 2S.
  • Dropping the negative root reasoning; ages cannot be negative.


Final Answer:
12 years

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