Alphabet analogy – find the missing code that matches a +9 shift ACEG : ? :: BDFH : KMOQ

Introduction / Context:
Letter-analogy questions test pattern recognition using the positions of letters in the alphabet. We must detect the transformation from one string to another and replicate it for a different string.

Given Data / Assumptions:

• Known mapping: BDFH → KMOQ.
• Target: ACEG → ?
• Alphabet indexing assumed A=1 … Z=26 with wrap-around if needed.

Concept / Approach:
Compute the displacement between corresponding letters of the known pair. If the displacement is constant for each position, apply the same displacement to the new source string to find the result.

Step-by-Step Solution:

Verification / Alternative check:
Check consistency: every letter advances by exactly 9 places; no wrap-around is needed here. The resulting string JLNP is listed among the options.

Why Other Options Are Wrong:

• NLPR/JNLO/LMNO: These do not reflect a strict +9 shift from A, C, E, G.

Common Pitfalls:
Applying an average shift only to the first letter or mixing step sizes across positions; ignoring constant-displacement requirement.

Final Answer:
JLNP