Letter–number analogy with mixed indexing Decode the pair MO → 13 11 and apply the same rule to HJ → ?

Introduction / Context:
This verbal–numeric analogy tests your ability to map letters to numbers using positional logic. The key is to infer the exact counting convention used in the first pair and then apply it consistently to the second pair.

Given Data / Assumptions:

• Alphabet positions from the start: A=1, B=2, …, Z=26.
• “Letters after X” means the count of letters strictly following X up to Z (i.e., not including X itself).
• Training pair: MO → 13 11.

Concept / Approach:
Observe that for M (the 13th letter), the first number is 13. For O, the second number is the count of letters after O up to Z. The letters after O are P through Z, which total 11. Thus, the code uses two different conventions: the first number is the normal alphabet index of the first letter; the second number is the “after-count” for the second letter.

Step-by-Step Solution:
For H: position from start = 8, but we must follow the MO pattern, which gave the first number directly as the first letter’s index → 8.For J: count letters after J up to Z. After J comes K…Z. Count = 26 − 11 + 1 = 16.Therefore HJ → 8 16.

Verification / Alternative check:
Recheck the “after” count quickly: K(11) through Z(26) inclusive gives 16 letters. The pattern matches the training pair logic.

Why Other Options Are Wrong:
19 17 and 16 18: Incorrect first number or swapped logic; they do not follow the mixed-index rule.8 10: Uses first-index correctly but miscounts the letters after J.

Common Pitfalls:
Confusing “reverse index” (27 − position) with the “letters-after” count or accidentally including the letter itself in the count.

Final Answer:
18 16