Difficulty: Easy
Correct Answer: 0.000012
Explanation:
Introduction / Context:Thermal expansion influences stresses in restrained members, joint detailing, and expansion joint spacing. A standard coefficient allows consistent temperature-effect calculations in steel structures.
Given Data / Assumptions:
Concept / Approach:The coefficient of linear thermal expansion, often denoted alpha, gives the change in length per unit length per degree Celsius. For structural steels, a typical value used in legacy Indian standards and many textbooks is about 12 × 10^-6 per °C, written as 0.000012 per °C per unit length.
Step-by-Step Solution:
Thermal elongation: ΔL = α * L * ΔT.Adopt α ≈ 0.000012 per °C for design checks.Use in restraint stress or movement joint calculations as required.Verification / Alternative check:Compare with common international references (≈ 11–13 × 10^-6 per °C); 12 × 10^-6 per °C sits within the typical range.
Why Other Options Are Wrong:Values like 0.000008 or 0.000016 are outside typical structural steel design assumptions in many codes and would misestimate movements.
Common Pitfalls:Mixing per °C with per °F; ignoring temperature gradients via composite action; neglecting restraint leading to unintended thermal stresses.
Final Answer:0.000012
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