Difficulty: Easy
Correct Answer: Greater
Explanation:
Introduction / Context: Enzyme inhibition is categorized by where and how an inhibitor binds. Competitive inhibitors compete directly with the substrate for the active site, while non-competitive inhibitors usually bind a topologically distinct allosteric site and modulate catalytic efficiency without occupying the active site itself.
Given Data / Assumptions:
Concept / Approach: By definition, a competitive inhibitor fits into the active site and blocks substrate access. A non-competitive inhibitor binds elsewhere and changes the enzyme’s conformation or catalytic rate constant; it does not depend on occupying the active site. Therefore, the competitive inhibitor’s ability to bind the active site is greater than that of a non-competitive inhibitor for the same enzyme.
Step-by-Step Solution: Recall definitions: competitive → active site; non-competitive → distinct site. Compare access to the active site: competitive has direct access; non-competitive typically does not. Conclude that the competitive inhibitor’s ability to bind the active site is greater. Select “Greater.”
Verification / Alternative check: Lineweaver–Burk (or modern non-linear fits) show competitive inhibition increases apparent Km; non-competitive reduces Vmax without changing Km, consistent with different binding locations.
Why Other Options Are Wrong: “Lesser” or “equal” contradict the definitions; “half” has no kinetic meaning; absolute zero is too strong since the question asks comparatively and classical non-competitive binding is not at the active site.
Common Pitfalls: Confusing non-competitive with uncompetitive inhibition; uncompetitive inhibitors bind only the enzyme–substrate complex, still not the free active site.
Final Answer: Greater.
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