Two-time ratios to present ages: Seven years ago, A : B = 3 : 4. Nine years hence, A : B = 7 : 8. What is B’s present age?

Difficulty: Medium

Correct Answer: 23 yr

Explanation:


Introduction / Context:
Again, two ratios at different times produce a solvable linear system for present ages. Translate carefully and solve systematically to avoid arithmetic slips.


Given Data / Assumptions:

  • (A − 7) : (B − 7) = 3 : 4
  • (A + 9) : (B + 9) = 7 : 8


Concept / Approach:
Cross-multiply each, reduce to standard linear form, and solve by elimination or substitution.


Step-by-Step Solution:

4(A − 7) = 3(B − 7) ⇒ 4A − 3B = 78(A + 9) = 7(B + 9) ⇒ 8A − 7B = −9Solve ⇒ A = 19, then 4A − 3B = 7 ⇒ 76 − 3B = 7 ⇒ B = 23


Verification / Alternative check:
Seven years ago: 12 : 16 = 3 : 4; in nine years: 28 : 32 = 7 : 8 ✓.


Why Other Options Are Wrong:
16, 19, 28 are not B’s present age under the constraints; only 23 fits.


Common Pitfalls:
Arithmetic slips when distributing and moving constants; ensure both persons’ ages shift by the same amount in each time frame.


Final Answer:
23 yr

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