Average-based relations among A, B, C: C is twice the average of A, B, C; A is half the average; B = 5 years. What is the average age of A, B, C?

Difficulty: Easy

Correct Answer: 10 years

Explanation:


Introduction / Context:
Average constraints can sometimes define each person directly in terms of the same average T, which then must satisfy its own definition T = (A + B + C)/3. Substituting these forms yields a single linear equation in T.


Given Data / Assumptions:

  • Let average be T.
  • C = 2T; A = T/2; B = 5.
  • Average definition: (A + B + C)/3 = T.


Concept / Approach:
Plug forms into the definition and solve for T. This ensures internal consistency and avoids guessing individual ages first.


Step-by-Step Solution:

(T/2 + 5 + 2T)/3 = T(2.5T + 5)/3 = T ⇒ 2.5T + 5 = 3T ⇒ 5 = 0.5T ⇒ T = 10


Verification / Alternative check:
Then A = 5, B = 5, C = 20; their average (5 + 5 + 20)/3 = 10, matching T.


Why Other Options Are Wrong:
15/12/9 do not satisfy both role definitions and the average identity simultaneously.


Common Pitfalls:
Using average of given numbers only (e.g., averaging 5 and 20) without enforcing all constraints together.


Final Answer:
10 years

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