Sizing parallel thyristors with derating A 750 A DC circuit uses identical thyristors each rated at 175 A. With a derating factor of 25% (i.e., each device carries only 75% of its nameplate current), how many thyristors must be placed in parallel?
-
A3
-
B4
-
C6
-
D10
-
E5
Answer
Correct Answer: 6
Explanation
Introduction / Context:When paralleling thyristors, current sharing is imperfect due to tolerances and temperature coefficients. A derating factor is applied so each device is loaded below its nominal rating, ensuring reliability. Calculating the required count is a straightforward but essential design step.
Given Data / Assumptions:
- Total circuit current Itotal = 750 A.
- Device nameplate Irated = 175 A.
- Derating 25% → usable per device Iusable = 0.75 * Irated.
Concept / Approach:
Number of devices in parallel n must satisfy n * Iusable ≥ Itotal. Use ceiling to ensure sufficient devices.
Step-by-Step Solution:
Iusable = 0.75 * 175 = 131.25 A.n ≥ 750 / 131.25 ≈ 5.714...Minimum integer n = 6.Verification / Alternative check:
Check margin: 6 * 131.25 = 787.5 A ≥ 750 A → acceptable.
Why Other Options Are Wrong:
3, 4, or 5 do not meet the required current with derating; 10 is over-conservative for the stated parameters.
Common Pitfalls:
Forgetting to apply derating; using rounding down instead of ceiling.
Final Answer:
6