Triggering a thyristor without gate current If the gate current of a thyristor is zero, conduction can still start only when the forward anode-to-cathode voltage exceeds:
-
AAbout 0.5 V
-
BThe forward breakover voltage
-
CThe on-state voltage
-
DThe peak working off-state forward voltage
-
EThe latching voltage
Answer
Correct Answer: The forward breakover voltage
Explanation
Introduction / Context:A silicon-controlled rectifier (SCR) is designed to turn on via a gate trigger. However, in the absence of gate current, it may still turn on if the anode-cathode voltage is raised high enough to avalanche the central junction—this is the forward breakover phenomenon. Knowing this is important for protection and dv/dt design.
Given Data / Assumptions:
- Gate current = 0 (no intentional trigger).
- Device is forward biased at the anode-cathode terminals.
- Static characteristics as per a standard SCR.
Concept / Approach:
With no gate drive, the SCR remains blocking until the anode-cathode voltage reaches the forward breakover voltage V_BO, where junction avalanche and regenerative feedback force the device into conduction. Under normal operation one avoids reaching V_BO to prevent uncontrolled turn-on; instead, a gate pulse is used at a lower forward voltage.
Step-by-Step Solution:
Set I_G = 0.Increase V_AK from zero: the device remains off until V_AK ≈ V_BO.At V_BO, regenerative action latches the SCR on → conduction begins.Verification / Alternative check:
Datasheets depict forward blocking and breakover regions; V_BO reduces with higher temperature or high dv/dt but is well above the on-state voltage.
Why Other Options Are Wrong:
0.5 V and on-state voltage describe conduction after turn-on, not the triggering threshold. 'Peak working off-state forward voltage' is a rating below breakover, not the trigger point.
Common Pitfalls:
Confusing breakover with latching/holding parameters; mistaking low on-state voltage for the trigger threshold.
Final Answer:
The forward breakover voltage