Duplicate head-start scenario (sanity check): In a 500 m race, speeds of A and B are in the ratio 3 : 4. A has a start of 140 m. By how many metres does A win?

Difficulty: Easy

Correct Answer: 20 m

Explanation:


Introduction / Context:
This repeats the earlier head-start calculation to confirm consistency across similar items.


Given Data / Assumptions:
Race 500 m; A has 140 m start → A runs 360 m. Speeds A:B = 3:4.


Concept / Approach:
B covers (4/3) times A’s distance in the same time. Compute B’s position when A finishes 360 m.


Step-by-Step Solution:

B's distance at A's finish = (4/3)*360 = 480 mWin margin = 500 − 480 = 20 m


Verification / Alternative check:
Consistent with proportional reasoning across similar tasks.


Why Other Options Are Wrong:
Mismatch the exact ratio implication.


Common Pitfalls:
Ignoring the head-start in required distance for A.


Final Answer:
20 m

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