Repeat of start + time-gap computation: In a 100 m race, A runs at 5 km/h, gives B a start of 8 m, and still beats B by 8 s. Find B’s speed.

Difficulty: Easy

Correct Answer: 4.14 Km/h

Explanation:

Introduction / Context:This is the same structure as a prior item; we recompute to confirm consistency.

Given Data / Assumptions:A’s speed = 5 km/h = 1.3889 m/s; B runs 92 m; B finishes 8 s after A.

Concept / Approach:Compute A’s finish time for 100 m, then add 8 s for B’s finish time over 92 m.

Step-by-Step Solution:

tA ≈ 72 s ⇒ tB = 80 svB = 92/80 = 1.15 m/s = 4.14 km/h

Verification / Alternative check:Matches earlier derived value.

Why Other Options Are Wrong:Numbers that do not match the precise timing.

Common Pitfalls:Mixing metres and kilometres without consistent conversions.

Final Answer:4.14 Km/h

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