Repeat of start + time-gap computation: In a 100 m race, A runs at 5 km/h, gives B a start of 8 m, and still beats B by 8 s. Find B’s speed.

Difficulty: Easy

Correct Answer: 4.14 Km/h

Explanation:


Introduction / Context:
This is the same structure as a prior item; we recompute to confirm consistency.


Given Data / Assumptions:
A’s speed = 5 km/h = 1.3889 m/s; B runs 92 m; B finishes 8 s after A.


Concept / Approach:
Compute A’s finish time for 100 m, then add 8 s for B’s finish time over 92 m.


Step-by-Step Solution:

tA ≈ 72 s ⇒ tB = 80 svB = 92/80 = 1.15 m/s = 4.14 km/h


Verification / Alternative check:
Matches earlier derived value.


Why Other Options Are Wrong:
Numbers that do not match the precise timing.


Common Pitfalls:
Mixing metres and kilometres without consistent conversions.


Final Answer:
4.14 Km/h

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