Difficulty: Easy
Correct Answer: 1 Mbps
Explanation:
Introduction / Context:
This question tests understanding of classic Ethernet hubs, collision domains, and half-duplex contention. Unlike a switch, a hub is a multiport repeater: all connected devices share the same 10 Mbps bandwidth and contend for access using CSMA/CD. Knowing how sharing works helps estimate per-host throughput to a server.
Given Data / Assumptions:
Concept / Approach:
On a hub, all ports form one collision domain and share the medium. Aggregate usable throughput among the contenders is bounded by 10 Mbps (less after CSMA/CD overhead). With roughly equal contention, a simple estimate divides the available rate by the number of active hosts.
Step-by-Step Solution:
Verification / Alternative check:
Packet captures show collisions and backoffs on a hub. Moving the users to a switch (separate collision domains per port) or increasing the server link rate changes the calculation. But with a hub, equal-share intuition matches lab measurements.
Why Other Options Are Wrong:
10 Mbps (D) would require a dedicated, non-contended link per host (a switch), which is not the case.
2 Mbps (C) and 100 kbps (A) do not match equal sharing of 10 Mbps among ten users.
Common Pitfalls:
Forgetting that hubs do not isolate collisions; assuming full-duplex or switched behavior; ignoring protocol overheads (which only reduce throughput further from the 1 Mbps estimate).
Final Answer:
1 Mbps
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