Difficulty: Easy
Correct Answer: Two
Explanation:
Introduction / Context:
From the letter set I, F, E, L (one each), determine how many everyday English words can be formed without repeating letters. Such problems test flexible word recognition and systematic checking of permutations.
Given Data / Assumptions:
Concept / Approach:
Two common words are immediately visible: LIFE and FILE. Each uses all four letters once, and both are frequent in everyday English. Other permutations such as “lief” also exist; however, “lief” is archaic/poetic and typically excluded in aptitude-test conventions favoring contemporary usage. Therefore, the accepted count is two.
Step-by-Step Solution:
1) Try common arrangements: LIFE ✓, FILE ✓.2) Evaluate variants: LIEF (archaic) generally excluded from “meaningful” in test context.3) Conclude that two standard words satisfy the constraint.
Verification / Alternative check:
Most exam keys treat “meaningful words” as everyday vocabulary entries. Under that norm, LIFE and FILE are counted; archaic or poetic forms like LIEF are not.
Why Other Options Are Wrong:
“None/One” miss at least one valid word; “Three” overstates by including archaic/less-accepted forms.
Common Pitfalls:
Over-including rare or archaic forms; always align with contemporary, general-use dictionaries for such tests.
Final Answer:
Two
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