Volume of iron in a hollow roller: A hollow cylindrical garden roller is 63 cm long with girth (outer circumference) 440 cm. Iron thickness is 4 cm. Find the volume of iron used (in cubic cm). Take π = 22/7.

Difficulty: Medium

Correct Answer: 107712 cubic cm

Explanation:


Introduction / Context:
For a hollow cylinder, volume of material equals π (R^2 − r^2) L. The girth gives the outer radius. Subtracting thickness yields the inner radius. Substitute and compute with π = 22/7.


Given Data / Assumptions:

  • Length L = 63 cm
  • Outer circumference C = 440 cm ⇒ R = C / (2π)
  • Thickness t = 4 cm ⇒ inner radius r = R − 4
  • π = 22/7


Concept / Approach:

  • Compute R, r, then V = π (R^2 − r^2) L = π (R − r)(R + r)L.


Step-by-Step Solution:

R = 440 / (2 * 22/7) = 440 * 7 / 44 = 70 cm; r = 70 − 4 = 66 cm.R^2 − r^2 = (70 − 66)(70 + 66) = 4 * 136 = 544.V = (22/7) * 544 * 63 = 22 * 544 * 9 = 107,712 cm3.


Verification / Alternative check:

Unit check: cm * cm2 = cm3; arithmetic matches stepwise factors.


Why Other Options Are Wrong:

  • 54982 / 57636 cm3: Arithmetic slips.
  • 56372 cubic m: Wrong unit (m vs cm).


Common Pitfalls:

  • Using diameter instead of radius after circumference.
  • Forgetting to subtract thickness from the radius (not diameter).


Final Answer:

107712 cubic cm

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