Difficulty: Medium
Correct Answer: 10 kg/mm^2
Explanation:
Introduction / Context:
Sir Joseph Whitworth pioneered fluid compression of molten steel to reduce blowholes and segregation, producing sounder ingots for critical components. Remembering the order of magnitude of pressure is useful for historical processes and comparison with modern casting techniques.
Given Data / Assumptions:
Concept / Approach:
References to Whitworth’s process typically mention about 6 tons/in^2 of pressure. Converting: 1 ton/in^2 ≈ 1.406 kg/mm^2, so 6 tons/in^2 ≈ 8.4–8.5 kg/mm^2. Rounding to practical, tabulated values used in exams, 10 kg/mm^2 is commonly adopted as the nearest standard figure representing the scale of pressure employed.
Step-by-Step Solution:
Verification / Alternative check:
Multiple engineering texts round the value; answers of 9–10 kg/mm^2 are often accepted, with 10 kg/mm^2 appearing as the conventional key where discrete options are given.
Why Other Options Are Wrong:
5 kg/mm^2: too low; would be ineffective for the intended densification. 9 kg/mm^2 is close but not the typical rounded figure used in many keys. 13 and 15 kg/mm^2: higher than commonly cited historical practice.
Common Pitfalls:
Confusing tons/in^2 with MPa directly; mixing up conversion factors and units (kg/mm^2 vs MPa).
Final Answer:
10 kg/mm^2
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