Odd-one-out (number properties) Which word does NOT belong with the others? Choose the single best answer.

Introduction / Context:
This question tests recognition of simple number properties. Four items are even integers when written as words, while one is an odd integer. Identifying parity (even versus odd) is a fundamental arithmetic skill, often used in quick odd-one-out problems.

Given Data / Assumptions:

• Options (as words): two, three, six, eight, ten
• Interpret each word as the corresponding integer.
• Exactly one should violate the common property shared by the rest.

Concept / Approach:
Check parity of each number. Even numbers are divisible by 2 without remainder. Odd numbers yield a remainder of 1 when divided by 2. Find the lone odd among otherwise even numbers.

Step-by-Step Solution:

Verification / Alternative check:
Consider secondary properties: two is prime, three is prime, while six, eight, and ten are composite. That comparison yields two primes, not one. However, parity produces a single unique outlier (only one odd), which serves as the decisive criterion in this set.

Why Other Options Are Wrong:

• Two: even.
• Six: even.
• Eight: even.
• Ten: even.

Common Pitfalls:
Overthinking with properties like primality or factors. The cleanest, most uniform distinction is parity, and only 'three' differs in that respect. Choose the simplest rule that yields a unique outlier.

Final Answer:
three