Difficulty: Medium
Correct Answer: Statements (b) and (c) are wrong
Explanation:
Introduction / Context:
This question probes understanding of molarity changes upon evaporation and the effects of dissolved salts on freezing and boiling points, as well as the distinction between mass fraction and mole fraction. Careful reasoning about definitions and colligative properties is essential in solution chemistry and process calculations.
Given Data / Assumptions:
Concept / Approach:
For statement (a): Molarity = moles of solute per litre of solution. Evaporation removes solvent, decreasing solution volume while moles of solute remain constant; hence molarity increases. For statement (b): Dissolved salts lower freezing point and raise boiling point relative to pure water; therefore, sea water has a lower freezing point and a higher boiling point, not both higher. For statement (c): Equal masses do not generally imply equal moles unless molar masses are identical; therefore, mole fractions are generally unequal.
Step-by-Step Solution:
Verification / Alternative check:
Colligative property formulas: ΔT_b = K_b * m and ΔT_f = K_f * m confirm qualitative trends for electrolytes in sea water.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing molarity (volume-based) with molality (mass of solvent-based). Evaporation does not change molality when only solvent is lost, but it does increase molarity.
Final Answer:
Statements (b) and (c) are wrong.
Discussion & Comments