Difficulty: Medium
Correct Answer: mole/m2·s
Explanation:
Introduction / Context:
In mass transfer problems involving diffusion through a stagnant gas film, the calculated “rate” is often a flux, i.e., moles transferred per unit area per unit time. Distinguishing between total rate and areal flux prevents dimensional errors when scaling from laboratory calculations to equipment design, such as evaporators or drying operations.
Given Data / Assumptions:
Concept / Approach:
The standard film theory gives a molar flux N_A in mol/m^2·s using N_A = k_c * (C_A,s − C_A,∞) or its equivalent for dilute species, where k_c has units of m/s and concentration difference has units of mol/m^3. Multiplying m/s by mol/m^3 yields mol/m^2·s. Thus, a numerical value near 10^-4 with the provided parameters corresponds to a flux, not a total rate integrated over area.
Step-by-Step Solution:
Verification / Alternative check:
Dimensional analysis alone confirms the unit: any mass transfer coefficient based on concentration difference delivers areal flux units. Converting to kmol/m^2·s would move the decimal by 3 orders of magnitude; cm^2 would change the numerical value by 10^4.
Why Other Options Are Wrong:
Common Pitfalls:
Confusing total evaporation rate with molar flux; always check whether an area normalization is implied by the governing equations.
Final Answer:
mole/m2·s.
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