Difficulty: Easy
Correct Answer: Active region
Explanation:
Introduction / Context:Bipolar junction transistors (BJTs) operate in distinct regions: cutoff, active, saturation, and breakdown. Recognizing which region provides linear amplification with nearly constant collector current is essential in amplifier circuit design.
Given Data / Assumptions:
Concept / Approach:
In the active region, IC is controlled primarily by the base current (IB) or base–emitter voltage (VBE), and remains nearly constant over a wide range of VCE. This property makes the active region suitable for amplification. In contrast, in saturation IC depends strongly on VCE, and in breakdown IC rises uncontrollably.
Step-by-Step Solution:
Cutoff: IB = 0, IC ≈ 0.Active: IC ≈ β * IB, nearly constant over VCE changes (until saturation or breakdown limits).Saturation: IC increases strongly with VCE, not constant.Breakdown: IC skyrockets, not constant.Verification / Alternative check:
Characteristic IC–VCE curves for BJTs show flat regions (active) where IC is almost constant, validating this answer.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:
Active region
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