CE Transistor Regions of Operation: In which region of a common-emitter (CE) bipolar junction transistor is the collector current almost constant?
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ASaturation region
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BActive region
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CBreakdown region
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DBoth saturation and active region
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ECutoff region
Answer
Correct Answer: Active region
Explanation
Introduction / Context:Bipolar junction transistors (BJTs) operate in distinct regions: cutoff, active, saturation, and breakdown. Recognizing which region provides linear amplification with nearly constant collector current is essential in amplifier circuit design.
Given Data / Assumptions:
- Configuration: Common-emitter (CE).
- Focus is on collector current (IC) behavior with varying collector–emitter voltage (VCE).
Concept / Approach:
In the active region, IC is controlled primarily by the base current (IB) or base–emitter voltage (VBE), and remains nearly constant over a wide range of VCE. This property makes the active region suitable for amplification. In contrast, in saturation IC depends strongly on VCE, and in breakdown IC rises uncontrollably.
Step-by-Step Solution:
Cutoff: IB = 0, IC ≈ 0.Active: IC ≈ β * IB, nearly constant over VCE changes (until saturation or breakdown limits).Saturation: IC increases strongly with VCE, not constant.Breakdown: IC skyrockets, not constant.Verification / Alternative check:
Characteristic IC–VCE curves for BJTs show flat regions (active) where IC is almost constant, validating this answer.
Why Other Options Are Wrong:
- Saturation: IC depends on VCE strongly.
- Breakdown: Destructive runaway.
- Both saturation and active: Misleading, only active region shows flat IC vs VCE behavior.
- Cutoff: No conduction at all.
Common Pitfalls:
- Confusing 'digital saturation' (switch closed) with 'linear constant current' behavior.
- Assuming collector current is constant in both saturation and active regions; in reality only active qualifies.
Final Answer:
Active region