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Which one of the following lists contains only valid Java language keywords (no identifiers or non-Java tokens)?

Difficulty: Easy

class, if, void, long, Int, continue
goto, instanceof, native, finally, default, throws
try, virtual, throw, final, volatile, transient
strictfp, constant, super, implements, do
byte, break, assert, switch, include

Correct Answer: goto, instanceof, native, finally, default, throws

Explanation:

Introduction / Context:
Knowing Java’s keyword set helps avoid using reserved words as identifiers and recognizes special meaning in code. Trick options often include almost-correct items (e.g., Int vs. int) or non-Java words.

Given Data / Assumptions:

We must select a list where every token is a Java keyword.

Concept / Approach:
Valid keywords include goto (reserved but unusable), instanceof, native, finally, default, throws. Non-keywords: Int (wrong case), virtual (not in Java), constant (not a keyword), include (not in Java). assert is a keyword since Java 1.4, but option E includes include, invalidating the entire set.

Step-by-Step Solution:

Option B → all six are keywords → correct.Option A → Int is not a keyword; should be lowercase int.Option C → virtual is not a Java keyword.Option D → constant is not a keyword (const exists but is reserved, not constant).Option E → include is not a Java keyword (C/C++ preprocessor concept).

Verification / Alternative check:
Consult any official list or attempt to compile variables named after these tokens.

Why Other Options Are Wrong:
Each contains at least one non-keyword.

Common Pitfalls:
Case sensitivity (Int vs. int) and language crossover terms like include or virtual.

Which one of the following lists contains only valid Java language keywords (no identifiers or non-Java tokens)?

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