Java keywords and for-loop tracing: identify the compile-time outcome of using “signed”.\n\npublic class Test {\n public static void main(String[] args) {\n signed int x = 10;\n for (int y = 0; y < 5; y++, x--)\n System.out.print(x + ", ");\n }\n}

Introduction / Context:
The snippet checks knowledge of Java’s primitive type system and reserved keywords. Unlike C/C++, Java does not use the “signed” or “unsigned” modifiers. All integer primitives (byte, short, int, long) are signed by definition except char, which is unsigned.

Given Data / Assumptions:

• Declaration attempts: signed int x = 10;
• Loop would otherwise print a countdown of x in tandem with y.

Concept / Approach:
The presence of “signed” in a variable declaration is not valid Java syntax. The compiler flags this with an error such as “not a statement” or “illegal start of type,” preventing any bytecode generation or execution.

Step-by-Step Solution:

Verification / Alternative check:
Replace with int x = 10; to compile and run. Then the output would be “10, 9, 8, 7, 6,” because x is decremented after each print due to the for-loop’s update expression.

Why Other Options Are Wrong:

• Numeric outputs assume successful compilation and execution.
• Runtime exception presupposes the program ran.
• Empty output is not specific; the correct outcome is a compile-time failure.

Common Pitfalls:
Porting C/C++ idioms to Java without adjusting for language differences; assuming signedness modifiers exist in Java.

Final Answer:
Compilation fails.