Eight persons — A, B, C, D, E, F, G, and H are sitting around a circular table facing toward the center, but not necessarily in the same order. Also, each of them is holding number cards from 2 to 9 (one card per person). The numbers on their cards are distinct. Consecutive numbered card holders are not sitting adjacent to each other. B is sitting second to the left of the person holding the card numbered 7. The person holding the card numbered 3 is sitting second to the right of E, who holds an even-numbered card greater than 4. C holds a card whose number is a prime number, but C is not sitting adjacent to either B or the person holding the card numbered 9. The person holding the card numbered 9 is sitting immediately to the right of A, who holds a card number divisible by both 2 and 4. The difference between the numbers on the cards hold by D and the person sitting opposite D is 3. The person holding the card numbered 2 sits third to the left of the person holding the card numbered 6. The sum of the numbers on the cards hold by G and the person sitting to G's immediate right is 11. The person holding the card numbered 4 is sitting opposite the person holding the card numbered 8. Which of the following is true about the seating arrangement?

### Concept & Logic This is a circular arrangement puzzle with a dual-variable twist (persons and distinct cards from 2 to 9). The golden rule here is that **consecutive numbered cards cannot be adjacent**. Facing the center means "Left" is clockwise and "Right" is anti-clockwise. ### Step-by-Step Solution 1. **Deduce $A$ and $E$'s cards:** * $A$ holds a card divisible by 2 and 4, so $A \in \{4, 8\}$. * Card 4 is opposite 8. * If $A = 8$, the person to $A$'s immediate right holds 9. Since 8 and 9 are consecutive, they cannot be adjacent. Thus, $A$ MUST be **4**. * Consequently, the person opposite $A$ holds **8**. * $E$ holds an even number $>4$, meaning $E \in \{6, 8\}$. Since $A$ and 8 are opposite, $E$ must be the one holding **8** to satisfy all conditions. 2. **Build the circle (Positions 1 to 8, Anti-Clockwise = Right):** * Let $A(4)$ be at Pos 1. * $E(8)$ is opposite at Pos 5. * Person with 9 is immediately right (anti-clockwise) of $A \rightarrow$ Pos 2 holds **9**. * Person with 3 is 2nd to the right of $E(8)$. From Pos 5, 2nd right is Pos 7. So, Pos 7 holds **3**. 3. **Place remaining cards (2, 5, 6, 7):** * Person with 2 is 3rd to the left (clockwise) of person with 6. * Placing 6 at Pos 6 puts 2 at Pos 3. This validly avoids consecutive adjacencies. * Only 5 and 7 remain for Pos 4 and Pos 8. Putting 7 at Pos 4 makes it adjacent to $E(8)$ (violating the consecutive rule). Thus, **7** is at Pos 8, and **5** is at Pos 4. 4. **Map the remaining Persons:** * $B$ is 2nd left of person with 7 (Pos 8). 2nd left (clockwise) of 8 is 6. Thus, $B$ is at Pos 6 (holding 6). * $D$ and opposite have a difference of 3. The only opposite pairs with a difference of 3 are at Pos 2 (9) and Pos 6 (6). Since $B$ is at Pos 6, $D$ must be at Pos 2 (holding 9). * $G$ + immediate right = 11. At Pos 8, $G(7)$ + right person $A(4)$ = 11. So $G$ is at Pos 8. * $C$ holds a prime and is not adjacent to $B(6)$ or 9. Pos 4 holds a prime (5) and is adjacent to 2 and 8, satisfying this. Thus, $C$ is at Pos 4. * $F$ and $H$ interchangeably occupy the remaining Pos 3 (holding 2) and Pos 7 (holding 3). 5. **Evaluate Options:** * $G$ is at Pos 8. The person holding 3 is at Pos 7. Positions 7 and 8 are adjacent. This statement is true. ### Exam Strategy & Shortcut Always start with the most restrictive negative constraints. The "no consecutive adjacent numbers" rule instantly solves the $A=4$ vs $A=8$ dilemma, creating a rigid anchor for the entire puzzle. ### Common Pitfall Confusing Left and Right in a circular arrangement. When everyone faces the center, Left is always Clockwise, and Right is always Anti-Clockwise. ### Final Answer Therefore, the correct answer is **G and the person holding card numbered 3 are seated adjacent to each other.**