C#.NET — What will this program print if the user types the non-numeric text "ABCD"? using System; namespace CuriousTabConsoleApplication { class MyProgram { static void Main(string[] args) { int index; int val = 88; int[] a = new int[5]; try { Console.Write("Enter a number: "); index = Convert.ToInt32(Console.ReadLine()); a[index] = val; } catch (Exception e) { Console.Write("Exception occurred"); } Console.Write("Remaining program"); } } }

Difficulty: Easy

Correct Answer: It will output: Exception occurred Remaining program

Explanation:


Introduction / Context:
This question checks your understanding of exception handling flow in C#.NET when invalid user input causes a conversion failure. It focuses on what executes inside a try/catch and what continues after the catch block.



Given Data / Assumptions:

  • The user inputs the non-numeric string "ABCD".
  • Convert.ToInt32 is used to parse the input into an integer index.
  • A generic catch (Exception) is present.
  • After the try/catch, the program writes "Remaining program".


Concept / Approach:
When Convert.ToInt32 receives a non-numeric string, it throws a FormatException. Since the code catches Exception (the base class), this FormatException is caught. Inside the catch block, the program prints "Exception occurred". After the catch completes, control moves beyond the try/catch, where the code prints "Remaining program". Therefore, both messages appear, in that order.



Step-by-Step Solution:

User enters "ABCD".Convert.ToInt32("ABCD") throws FormatException.catch (Exception e) catches the exception and executes Console.Write("Exception occurred").Execution resumes after the catch; Console.Write("Remaining program") runs.


Verification / Alternative check:
If you replaced catch (Exception) with a more specific catch (FormatException), behavior would be identical for this input. Removing the catch would terminate the program and show an unhandled exception message.



Why Other Options Are Wrong:

  • Only one of the two messages: ignores that code continues after the catch.
  • "Remaining program Exception occurred": reverse order; the catch executes before the final print.
  • Assigning 88 to a[0]: no assignment occurs because parsing fails before indexing.


Common Pitfalls:
Assuming that a catch stops all further execution. Only the protected statements are skipped; code after the try/catch still runs unless the program is terminated or rethrows.



Final Answer:
It will output: Exception occurred Remaining program

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